Question

1. solve each equation. round to the nearest tenth

\\(\frac{-6}{7} = \frac{f + 3}{12}\\)

Explanation:

Step1: Cross-multiply to eliminate fractions

$$-6 \times 12 = 7(f+3)$$

Step2: Calculate both sides

$$-72 = 7f + 21$$

Step3: Isolate the term with $f$

$$7f = -72 - 21$$
$$7f = -93$$

Step4: Solve for $f$

$$f = \frac{-93}{7}$$

Step5: Round to nearest tenth

$$f \approx -13.3$$

Answer:

$f \approx -13.3$