Question

solve each system of equations by substitution.

1. \

$$\begin{cases} x + 3y = 9 \\\\ 4x - 2y = -6 \\end{cases}$$

6.

Explanation:

Step1: Isolate x in first equation

$x = 9 - 3y$

Step2: Substitute x into second equation

$4(9 - 3y) - 2y = -6$

Step3: Simplify and solve for y

$36 - 12y - 2y = -6$
$36 - 14y = -6$
$-14y = -6 - 36$
$-14y = -42$
$y = 3$

Step4: Substitute y back to find x

$x = 9 - 3(3)$
$x = 9 - 9$
$x = 0$

Answer:

$x=0$, $y=3$