Question

solve the equation using square roots. select the solution(s).
$2x^2 - 98 = 0$
$x = -9$ $x = -8$ $x = -7$
$x = -4$ $x = -3$ $x = -2$
$x = 1$ $x = 2$ $x = 3$
$x = 6$ $x = 7$ $x = 8$

Explanation:

Step1: Isolate the \(x^2\) term

First, we add 98 to both sides of the equation \(2x^2 - 98 = 0\) to get \(2x^2=98\). Then, we divide both sides by 2, so \(x^2=\frac{98}{2}=49\).

Step2: Take the square root of both sides

Taking the square root of both sides, we have \(x = \pm\sqrt{49}=\pm7\). So the solutions are \(x = - 7\) and \(x = 7\).

Answer:

\(x=-7\), \(x = 7\) (corresponding to the options: \(x=-7\) and \(x = 7\))