Question

solve the equation for the value of x.
\\(\frac{4x - (6x - 2)}{32}=\\)

Explanation:

Step1: Expand the left - hand side

$4x-(6x - 2)=4x-6x + 2=-2x + 2$

Step2: Set up the new equation

$-2x + 2=32$

Step3: Isolate the term with x

Subtract 2 from both sides: $-2x=32 - 2=30$

Step4: Solve for x

Divide both sides by - 2: $x=\frac{30}{-2}=-15$

Answer:

$x=-15$