Question

solve the following system of equations.
$9x + 6y = -3$
$5x + 6y = 9$
$x = \square$
$y = \square$

Explanation:

Step1: Subtract equations to eliminate $y$

$$(9x + 6y) - (5x + 6y) = -3 - 9$$
$$4x = -12$$

Step2: Solve for $x$

$$x = \frac{-12}{4} = -3$$

Step3: Substitute $x=-3$ into second equation

$$5(-3) + 6y = 9$$
$$-15 + 6y = 9$$

Step4: Solve for $y$

$$6y = 9 + 15 = 24$$
$$y = \frac{24}{6} = 4$$

Answer:

$x = -3$
$y = 4$