Question

8.6 solve radical equations (homework)
score: 15/16 answered: 15/16
question 16
find all real solutions:
2\sqrt{3y + 8}-12 = 0
y = (if no solution exists, enter dne)

Explanation:

Step1: Isolate the square - root term

Add 12 to both sides of the equation $2\sqrt{3y + 8}-12 = 0$.
$2\sqrt{3y + 8}=12$

Step2: Solve for the square - root term

Divide both sides by 2.
$\sqrt{3y + 8}=6$

Step3: Eliminate the square - root

Square both sides of the equation.
$(\sqrt{3y + 8})^2=6^2$
$3y + 8 = 36$

Step4: Solve for y

Subtract 8 from both sides: $3y=36 - 8=28$.
Then divide both sides by 3: $y=\frac{28}{3}$

Answer:

$\frac{28}{3}$