Question

solve for y.
$-\frac{1}{6}+y=\frac{3}{5}$
simplify your answer as much as possible.
$y = square$

Explanation:

Step1: Add $\frac{1}{6}$ to both sides

To isolate \( y \), we add \(\frac{1}{6}\) to both sides of the equation \(-\frac{1}{6} + y = \frac{3}{5}\). This gives us \( y = \frac{3}{5} + \frac{1}{6} \).

Step2: Find a common denominator and add

The common denominator of 5 and 6 is 30. So we rewrite the fractions: \(\frac{3}{5} = \frac{3\times6}{5\times6} = \frac{18}{30}\) and \(\frac{1}{6} = \frac{1\times5}{6\times5} = \frac{5}{30}\). Then we add them: \( y = \frac{18}{30} + \frac{5}{30} = \frac{18 + 5}{30} = \frac{23}{30} \).

Answer:

\( y = \frac{23}{30} \)