Question

solving a quadratic equation when a ≠ 1 by completing the square
consider ( 8x^2 - 48x = -104 )
write the equation so that
a = 1 ( x^2 + square ) ( x = square )
complete
complete the square:
( x^2 - 6x + square = -13 + square )
complete
factor the trinomial and simplify
( (x + square)^2 = square )
done

Explanation:

Step1: Rewrite left side as trinomial

$x^2 - 6x + 9 = -13 + 9$

Step2: Simplify both sides

$x^2 - 6x + 9 = -4$

Step3: Factor the perfect trinomial

$(x - 3)^2 = -4$

Answer:

First blank: $\boldsymbol{-3}$
Second blank: $\boldsymbol{-4}$