Question

2 the specific heat of wood is 2.03 j/g °c. how much heat is needed to convert 550 g of wood at 0°c to 10°c? 3. to what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat capacity is 0.5 j/g°c? the initial temperature of the glass is 20.0°c.

Explanation:

Step1: Identify the formula

The formula for heat is $Q = mc\Delta T$, where $Q$ is heat, $m$ is mass, $c$ is specific - heat capacity, and $\Delta T$ is the change in temperature.

Step2: Calculate $\Delta T$ for wood problem

For the wood problem, $\Delta T=T_2 - T_1=10^{\circ}C - 0^{\circ}C = 10^{\circ}C$, $m = 550g$, and $c = 2.03J/g^{\circ}C$.
$Q=mc\Delta T=550\times2.03\times10$

Step3: Solve for $Q$ in wood problem

$Q = 550\times2.03\times10=11165J$

Step4: Rearrange formula for glass problem

For the glass problem, from $Q = mc\Delta T$, we can solve for $\Delta T$: $\Delta T=\frac{Q}{mc}$. Given $Q = 5275J$, $m = 50.0g$, and $c = 0.5J/g^{\circ}C$.
$\Delta T=\frac{5275}{50.0\times0.5}=\frac{5275}{25}=211^{\circ}C$

Step5: Calculate final temperature for glass problem

The final temperature $T_2=T_1+\Delta T$. Given $T_1 = 20.0^{\circ}C$.
$T_2=20.0 + 211=231^{\circ}C$

Answer:

1. The heat needed for wood is $11165J$.
2. The final temperature of the glass is $231^{\circ}C$.