QUESTION IMAGE
Question
spiral review determine a relationship between the x- and y-values. write an equation. (lesson 4-3) 40.
| x | 1 | 2 | 3 | 4 |
| y | 6 | 7 | 8 | 9 |
41.
| x | 1 | 2 | 3 | 4 |
| y | 3 | 6 | 9 | 12 |
42.
| x | 1 | 2 | 3 | 4 |
| y | -9 | -8 | -7 | -6 |
tell whether each equation is a direct variation. if so, identify the constant of variation. (lesson 5-5) 43. $x = 2y$ 44. $y = -6x$ 45. $y - 1 = x$ solve each system by substitution. (lesson 6-2) 46. $\
$ 47. $\
$ 48. $\
$ 6-3 solving systems by elimination
Questions 40-42: Determine x-y relationship, write equation
40. Step1: Find y-x difference
$6-1=5$, $7-2=5$, $8-3=5$, $9-4=5$
40. Step2: Write linear equation
$y = x + 5$
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41. Step1: Find y/x ratio
$\frac{3}{1}=3$, $\frac{6}{2}=3$, $\frac{9}{3}=3$, $\frac{12}{4}=3$
41. Step2: Write proportional equation
$y = 3x$
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42. Step1: Find y+x sum
$-9+1=-8$, $-8+2=-6$, $-7+3=-4$, $-6+4=-2$ (or find y-x difference: $-9-1=-10$, $-8-2=-10$, $-7-3=-10$, $-6-4=-10$)
42. Step2: Write linear equation
$y = x - 10$
A direct variation has the form $y=kx$ (k is constant, no constant term). Rearrange each equation to check this form.
- For $x=2y$, rearrange to $y=\frac{1}{2}x$: fits $y=kx$.
- For $y=-6x$: directly fits $y=kx$.
- For $y-1=x$, rearrange to $y=x+1$: has a constant term, so not direct variation.
46. Step1: Substitute $y=x-1$ into second equation
$x + (x - 1) = 10$
46. Step2: Solve for x
$2x - 1 = 10 \implies 2x=11 \implies x=\frac{11}{2}=5.5$
46. Step3: Solve for y
$y = 5.5 - 1 = 4.5$
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47. Step1: Substitute $x=y-5$ into second equation
$2(y - 5) + 1 = y$
47. Step2: Simplify and solve for y
$2y - 10 + 1 = y \implies 2y - y = 9 \implies y=9$
47. Step3: Solve for x
$x = 9 - 5 = 4$
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48. Step1: Substitute $y=2x-1$ into second equation
$x - (2x - 1) = 3$
48. Step2: Simplify and solve for x
$x - 2x + 1 = 3 \implies -x=2 \implies x=-2$
48. Step3: Solve for y
$y = 2(-2) - 1 = -5$
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- $y = x + 5$
- $y = 3x$
- $y = x - 10$
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