Question

sqrt{360^{2}+480^{2}} = 600 ft
now find cos θ
cos θ=\frac{360}{600}
= 0.6 (type an integer or a decimal )
substitute cos θ = 0.6 and the upward velocity \frac{dy}{dt}=40 ft/s into the equation from the derivatives to find \frac{dθ}{dt}
\frac{dθ}{dt}=\frac{cos^{2}θ}{360}\frac{dy}{dt}
=\frac{(0.6)^{2}(40)}{360}
= square (round to two decimal places as needed )

Explanation:

Step1: Calculate the value of the fraction

First, calculate $(0.6)^2(40)$.
$(0.6)^2\times40 = 0.36\times40=14.4$

Step2: Divide the result by 360

Now, divide 14.4 by 360.
$\frac{14.4}{360}=0.04$

Answer:

$0.04$