Question

start by reflecting the vertices, q, r, s, and t, of quadrilateral qrst over the x - axis.
original point
q (-9,4)
r (-7,5)
s (-6,3)
t (-8,1)
points after reflection over x - axis
q
r
s
t

Explanation:

Step1: Recall reflection rule

When reflecting a point $(x,y)$ over the x - axis, the rule is $(x,y)\to(x, - y)$.

Step2: Apply rule to point T

For point T with coordinates $(-8,1)$, after reflection over the x - axis, the x - coordinate remains the same and the y - coordinate changes sign. So, $T(-8,1)\to T'(-8,-1)$.

Step3: Apply rule to point S

For point S with coordinates $(-6,3)$, after reflection over the x - axis, $S(-6,3)\to S'(-6,-3)$.

Step4: Apply rule to point R

For point R with coordinates $(-7,5)$, after reflection over the x - axis, $R(-7,5)\to R'(-7,-5)$.

Step5: Apply rule to point Q

For point Q with coordinates $(-9,4)$, after reflection over the x - axis, $Q(-9,4)\to Q'(-9,-4)$.

Answer:

T': (-8,-1), S': (-6,-3), R': (-7,-5), Q': (-9,-4)