Question

step 2: \\(\frac{\frac{y - 2x^2}{x^2y}}{\frac{y - 2x^2}{1}}\\)
step 3: \\(\frac{y - 2x^2}{x^2y} cdot \frac{1}{y - 2x^2}\\)
what should mrs. cho do next?
\\(\circ\\) find a common denominator for the two fractions.
\\(\circ\\) divide the numerator and denominator of the first fraction by \\(x^2\\) and \\(y\\).
\\(\circ\\) multiply the numerators, multiply the denominators, and then simplify.
\\(\circ\\) multiply the first fraction by the reciprocal of the second fraction.

Explanation:

Step1: Analyze current expression

We have $\frac{y-2x^2}{x^2 y} \cdot \frac{1}{y-2x^2}$, a product of fractions.

Step2: Recall fraction multiplication rule

To multiply fractions, multiply numerators, multiply denominators, then simplify common factors.

Answer:

Multiply the numerators, multiply the denominators, and then simplify.