Question

1. a student performs an experiment with three unknown fluids and obtains the following measurements: fluid a: mass = 2060 g, volume = 2000ml fluid b: mass = 672g, volume = 850 ml fluid c: mass = 990g, volume = 1100ml draw how the fluids would be layered if they were combined in a beaker. 8. use your density skills to find the identity of the following mystery objects: table of densities solids density g/cm³ solids density g/cm³ marble 2.56 copper 8.92 quartz 2.64 gold 19.32

Explanation:

Step1: Calculate density of Fluid A

$
ho_A=\frac{m_A}{V_A}=\frac{2060g}{2000cm^3}=1.03g/cm^3$ (since $1mL = 1cm^3$)

Step2: Calculate density of Fluid B

$
ho_B=\frac{m_B}{V_B}=\frac{672g}{850cm^3}\approx0.79g/cm^3$

Step3: Calculate density of Fluid C

$
ho_C=\frac{m_C}{V_C}=\frac{990g}{1100cm^3}=0.9g/cm^3$

Step4: Determine layering

The most - dense fluid (A) is at the bottom, then C, and least - dense B at the top.

Answer:

Fluid B on top, then Fluid C, and Fluid A at the bottom.