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Question
suppose an isolated tower is 30 meters high. according to umans estimate, that means a leader that comes within 60 meters will be intercepted by an upward - going leader from the object. an area with a radius of 60 meters is roughly 11,310 square meters. if the ground - strike frequency where the tower is located is 5 per square km per year, what is frequency with which the tower will likely be struck?
a. $5.65\times10^{-2}$ flashes per year
b. $2.83\times10^{-2}$ flashes per year
c. 20 flashes per year
d. 20,000 flashes per year
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Step1: Convert area to square kilometers
The area of the region around the tower is 11,310 square meters. Since 1 square km = \(10^6\) square meters, we convert the area: \(A=\frac{11310}{10^6}\) square km.
Step2: Calculate the strike frequency
The ground - strike frequency is 5 per square km per year. So the strike frequency for the tower's area is \(f = 5\times A\). Substitute \(A=\frac{11310}{10^6}\) into the formula: \(f = 5\times\frac{11310}{10^6}=\frac{56550}{10^6}=5.655\times 10^{-2}\approx5.65\times 10^{-2}\) flashes per year.
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a. \(5.65\times 10^{-2}\) flashes per year