Question

suppose 8 quarts of a solution that is 45% antifreeze is mixed with 12 quarts of a solution that is 33% antifreeze. answer the questions below. do not do any rounding. (a) how many quarts of antifreeze are in the resulting mixture? \\(\square\\) quarts (b) what percentage of the resulting mixture is antifreeze? \\(\square\\)%

Explanation:

Step1: Calculate antifreeze from first solution

Antifreeze amount: $8 \times 0.45 = 3.6$ quarts

Step2: Calculate antifreeze from second solution

Antifreeze amount: $12 \times 0.33 = 3.96$ quarts

Step3: Total antifreeze in mixture

Sum the two amounts: $3.6 + 3.96 = 7.56$ quarts

Step4: Total volume of mixture

Sum the solution volumes: $8 + 12 = 20$ quarts

Step5: Calculate percentage of antifreeze

Divide total antifreeze by total volume, multiply by 100: $\frac{7.56}{20} \times 100 = 37.8$

Answer:

(a) 7.56 quarts
(b) 37.8 %