Question

suppose you spin the spinner below 5 times. which probabilities do you need in order to calculate p(getting a on 2 or fewer spins)? p(0 successes) p(1 success) p(2 successes) p(3 successes) p(4 successes) p(5 successes) complete p(getting a on 2 or fewer spins)= done

Explanation:

Step1: Define the event

We want to find $P(\text{getting A on 2 or fewer spins})$. This is the sum of the probabilities of getting A 0 times, 1 time, and 2 times.

Step2: Identify relevant probabilities

We need $P(0\text{ successes})$, $P(1\text{ success})$, and $P(2\text{ successes})$ as these are the individual - event probabilities that make up the desired compound event.

Answer:

$P(\text{getting A on 2 or fewer spins})=P(0\text{ successes}) + P(1\text{ success})+P(2\text{ successes})$