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Question
systems of equations: substitution #1
use substitution to solve each system of equations.
1.
y = 6
-x + y = 2
(__ , __)
2.
x = 5
3x - 2y = 9
(__ , __)
3.
4x = -8
2x + 5y = 6
(__ , __)
4.
y = -5x
6x + y = 2
(__ , __)
5.
x = 9y
3y - 3x = 24
(__ , __)
6.
y - x = -8
2x - 16 = y
(__ , __)
7.
y = 3x + 1
y = 8x - 4
(__ , __)
8.
x + y = 0
5x + 4y = 6
(__ , __)
9.
2y = -2x + 6
x - 5y = -15
(__ , __)
10.
5x + y = 2
20x + 3y = -4
(__ , __)
11.
-8x + 2y = -14
4x - 6y = 22
(__ , __)
12.
2x + 4y = -18
5x - 10y = -5
(__ , __)
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Problem 1
Step1: Substitute $y=6$ into 2nd equation
$-x + 6 = 2$
Step2: Solve for $x$
$-x = 2 - 6 \implies -x = -4 \implies x=4$
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(1):
$(4, 6)$
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Problem 2
Step1: Substitute $x=5$ into 2nd equation
$3(5) - 2y = 9$
Step2: Simplify and solve for $y$
$15 - 2y = 9 \implies -2y = 9-15 \implies -2y=-6 \implies y=3$