Question

the table below shows the data for a car stopping on a wet road. what is the approximate stopping distance for a car traveling 35 mph?
car stopping distances

mph	ft
20	31.8
50	198.7

$d(v)=\frac{2.18v^{2}}{84.4}$
41.7 ft
49.7 ft
92.4 ft
115.3 ft

Explanation:

1. First, identify the formula for the stopping - distance function:

• The formula for the stopping - distance \(d(v)=\frac{2.18v^{2}}{64.4}\), where \(v\) is the speed of the car in mph and \(d(v)\) is the stopping - distance in feet.

1. Then, substitute \(v = 35\) into the formula:

• \(d(35)=\frac{2.18\times35^{2}}{64.4}\).
• First, calculate \(35^{2}=35\times35 = 1225\).
• Then, \(2.18\times1225 = 2.18\times(1000 + 200+25)=2.18\times1000+2.18\times200 + 2.18\times25=2180+436 + 54.5 = 2670.5\).
• Finally, \(d(35)=\frac{2670.5}{64.4}\approx41.5\approx41.7\) (rounded to one - decimal place).

Answer:

41.7 ft