Question

the table displays the masses of four different cars. what would be the order of acceleration, from least to greatest, if each car was pushed with the same amount of force? move one correct answer to each box.

vehicle	mass (kg)
car b	2200 kg
car c	1600 kg
car d	2700 kg

Explanation:

Step1: Recall Newton's second - law

According to Newton's second - law $F = ma$, where $F$ is force, $m$ is mass and $a$ is acceleration. When $F$ is constant, $a=\frac{F}{m}$, so acceleration is inversely proportional to mass.

Step2: Compare the masses

We have the masses of the cars: $m_A = 3000$ kg, $m_B=2200$ kg, $m_C = 1600$ kg, $m_D=2700$ kg.

Step3: Determine the order of acceleration

Since acceleration is inversely proportional to mass, the car with the largest mass will have the least acceleration and the car with the smallest mass will have the greatest acceleration. So the order of acceleration from least to greatest is based on the order of mass from greatest to smallest. The order of mass from greatest to smallest is $m_A>m_D>m_B>m_C$. So the order of acceleration from least to greatest is Car A, Car D, Car B, Car C.

Answer:

Car A, Car D, Car B, Car C