Question

the table on the left shows the distribution of scores on a quiz taken in an algebra class. what is the median? score freq 6 11 8 26 10 27 12 32 14 31 16 12 18 15 20 7

Explanation:

Step1: Calculate total frequency

$11 + 26+27 + 32+31+12+15+7=151$

Step2: Find the position of the median

Since $n = 151$ (odd), the median is at the $\frac{n + 1}{2}=\frac{151+ 1}{2}=76$ - th position.

Step3: Cumulative - frequency calculation

For score 6, cumulative frequency $cf_1=11$.
For score 8, cumulative frequency $cf_2=11 + 26=37$.
For score 10, cumulative frequency $cf_3=37+27 = 64$.
For score 12, cumulative frequency $cf_4=64 + 32=96$.
Since the 76 - th value lies in the group with score 12 (because 64 < 76 <= 96).

Answer:

12