QUESTION IMAGE
Question
- tall sunflowers are dominant to short, while yellow-colored flowers are dominant to orange. cross a plant that is heterozygous for both traits with a plant that is heterozygous for height, but homozygous dominant for flower color. what will be the possible genotypes and phenotypes of the offspring? show your work as a punnett square and write your answers as a phenotypic ratio.
- using the punnett square that you created for problem #7, answer the following
Step1: Define allele symbols
Let \(T\) = tall (dominant), \(t\) = short (recessive); \(Y\) = yellow (dominant), \(y\) = orange (recessive)
Step2: Identify parent genotypes
Parent 1 (heterozygous for both): \(TtYy\), gametes: \(TY, Ty, tY, ty\)
Parent 2 (heterozygous height, homozygous dominant color): \(TtYY\), gametes: \(TY, TY, tY, tY\)
Step3: Build Punnett square
| \(TY\) | \(Ty\) | \(tY\) | \(ty\) | |
|---|---|---|---|---|
| \(TY\) | \(TTYY\) | \(TTYy\) | \(TtYY\) | \(TtYy\) |
| \(tY\) | \(TtYY\) | \(TtYy\) | \(ttYY\) | \(ttYy\) |
| \(tY\) | \(TtYY\) | \(TtYy\) | \(ttYY\) | \(ttYy\) |
Step4: Classify phenotypes
- Tall, yellow: \(TTYY, TTYy, TtYY, TtYy\) (12 total)
- Short, yellow: \(ttYY, ttYy\) (4 total)
Step5: Calculate phenotypic ratio
Simplify \(12:4\) to \(3:1\)
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Possible Genotypes:
\(TTYY\), \(TTYy\), \(TtYY\), \(TtYy\), \(ttYY\), \(ttYy\)
Phenotypic Ratio:
3 tall, yellow sunflowers : 1 short, yellow sunflower