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Question
a tennis ball is dropped from a certain height. its height in feet is given by $h(t)=-16t^{2}+14$ where $t$ represents the time in seconds after launch. what is the balls initial height? answer attempt 1 out of 2 feet submit answer
Step1: Identify initial time
Initial time $t = 0$.
Step2: Substitute $t = 0$ into function
Substitute $t=0$ into $h(t)=-16t^{2}+14$. So $h(0)=-16\times0^{2}+14$.
Step3: Calculate the result
Since $-16\times0^{2}=0$, then $h(0)=14$.
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