Question

a tennis ball is dropped from a certain height. its height in feet is given by $h = -16t^{2}+17$ where $t$ represents the time in seconds after launch. what is the balls initial height?

Explanation:

Step1: Identify initial time

Initial time means $t = 0$.

Step2: Substitute $t = 0$ into height - formula

Substitute $t=0$ into $h=-16t^{2}+17$. So $h=-16\times(0)^{2}+17$.

Step3: Calculate the height

Since $-16\times(0)^{2}=0$, then $h = 17$.

Answer:

17