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Question
terrance is using the formula a = 4b + 4c to solve a problem on his homework worksheet. which of the following would not be an equivalent equation when solving the formula for c? c = a - 4b / 4, c = 1 / 4a - b, c = a - 4b / 4, c = 4a - 4b
Step1: Isolate the terms with c.
$A = 4p+4c$ can be rewritten as $4c=A - 4p$.
Step2: Solve for c.
Divide both sides by 4, so $c=\frac{A - 4p}{4}=\frac{A}{4}-p$.
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The equation that is not equivalent to the formula for c when solving $A = 4p + 4c$ for c is $c=\frac{1}{4}A - p$ (assuming this was one of the options and was mis - typed in the problem statement as the correct form after solving should be $c=\frac{A}{4}-p$), $c=\frac{A - 4p}{4}$, $c = \frac{A}{4}-p$ are correct forms after solving for c from $A = 4p+4c$. Without seeing all the options clearly, if we assume the incorrect one among the given choices is the one with wrong coefficient placement or wrong algebraic manipulation result. If we assume the options are:
- $c=\frac{A}{4}-p$
- $c=\frac{1}{4}A - p$ (wrong form if the correct manipulation is done as above)
- $c=\frac{A - 4p}{4}$
- $c = 4A-4p$ (clearly wrong as it is not the result of correct algebraic steps to isolate c from $A = 4p + 4c$)
The answer would be the option with incorrect algebraic manipulation for solving for c from $A = 4p+4c$. If we assume the incorrect option is the one with wrong coefficient or wrong algebraic steps result like $c = 4A-4p$ (this is just an example based on the way the problem seems to be structured asking for non - equivalent form).