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Question
there is a population of 15,500 bacteria in a colony. if the number of bacteria doubles every 234 hours, what will the population be 936 hours from now? bacteria
Step1: Find the number of doubling periods
To find how many times the bacteria population doubles in 936 hours, we divide the total time by the time it takes to double. So, we calculate $\frac{936}{234}$.
$\frac{936}{234} = 4$
Step2: Calculate the final population
The initial population is 15,500. Each doubling period multiplies the population by 2. After 4 doubling periods, the population will be $15500\times2^4$.
First, calculate $2^4 = 16$. Then, $15500\times16 = 248000$
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248000