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Question
if these two shapes are similar, what is the measure of the missing length k? 6 in 2 in 1 in k k = inches
Step1: Set up proportion
For similar shapes, the ratios of corresponding sides are equal. Let the ratio of the sides of the two triangles be $\frac{6}{2}=\frac{k}{1}$.
Step2: Solve for k
Cross - multiply the proportion: $6\times1 = 2\times k$. Then $k=\frac{6\times1}{2}$.
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