Question

the time constant for a 2 h coil connected in series with a 50 ω resistor is _. 0.25 0.04 100 25

Explanation:

Step1: Recall the time constant formula for an RL circuit

The time constant \(\tau\) for an RL (resistor - inductor) series circuit is given by the formula \(\tau=\frac{L}{R}\), where \(L\) is the inductance of the inductor and \(R\) is the resistance of the resistor.

Step2: Identify the values of \(L\) and \(R\)

From the problem, we know that the inductance \(L = 2\space H\) (henries) and the resistance \(R=50\space\Omega\) (ohms).

Step3: Substitute the values into the formula

Substitute \(L = 2\) and \(R = 50\) into the formula \(\tau=\frac{L}{R}\). We get \(\tau=\frac{2}{50}\).

Step4: Calculate the result

\(\frac{2}{50}=0.04\).

Answer:

0.04