Question

4 tokala swims \\(\frac{2}{3}\\) mile on monday, \\(\frac{3}{4}\\) mile on wednesday, and \\(\frac{5}{6}\\) mile on friday. what is the total distance tokala swims on those three days? show your work.

Explanation:

Step1: Identify the distances

Tokala swims $\frac{2}{3}$ mile on Monday, $\frac{3}{4}$ mile on Wednesday, and $\frac{5}{6}$ mile on Friday.

Step2: Find a common denominator

The denominators are 3, 4, and 6. The least common denominator (LCD) of 3, 4, and 6 is 12.

Step3: Convert fractions to have LCD

• For $\frac{2}{3}$: $\frac{2\times4}{3\times4}=\frac{8}{12}$
• For $\frac{3}{4}$: $\frac{3\times3}{4\times3}=\frac{9}{12}$
• For $\frac{5}{6}$: $\frac{5\times2}{6\times2}=\frac{10}{12}$

Step4: Add the fractions

$\frac{8}{12}+\frac{9}{12}+\frac{10}{12}=\frac{8 + 9 + 10}{12}=\frac{27}{12}$

Step5: Simplify the result

$\frac{27}{12}=\frac{9}{4}=2\frac{1}{4}$

Answer:

The total distance Tokala swims on those three days is $\boldsymbol{2\frac{1}{4}}$ miles (or $\boldsymbol{\frac{9}{4}}$ miles).