Question

a train has 5 part, the locomotive is $\frac{1}{3}$ of the train, the middle part is $\frac{1}{12}$ of the locomotive. what is the value of the passenger side?
locomotive is $\frac{1}{3}$ of train. if t
the middle part is $\frac{1}{12}$ of locomotive left
$3×\frac{1}{12}=$

Explanation:

Step1: Define total train length

Let total train length = $L$.

Step2: Assign lengths to parts

Locomotive: $\frac{1}{3}L$, Middle: $\frac{1}{12}L$, Passenger cars: $L - \frac{1}{3}L - \frac{1}{12}L$

Step3: Simplify passenger car length

$L - \frac{4}{12}L - \frac{1}{12}L = \frac{7}{12}L$

Step4: Use given locomotive length

$\frac{1}{3}L = 4$ ft/min $\times 3$ min $= 12$ ft

Step5: Solve for total length $L$

$L = 12 \times 3 = 36$ ft

Step6: Calculate passenger car length

$\frac{7}{12} \times 36 = 21$ ft

Answer:

21 feet