Question

1. a train speeds up with a constant acceleration from 6.00 m/s to 22.0 m/s in 8.00 s. how far does it travel in that time?

Explanation:

Step1: Find average velocity

Average velocity is the average of initial and final velocities.
$\bar{v} = \frac{v_0 + v}{2} = \frac{6.00\ \text{m/s} + 22.0\ \text{m/s}}{2} = 14.0\ \text{m/s}$

Step2: Calculate distance traveled

Distance equals average velocity multiplied by time.
$d = \bar{v} \times t = 14.0\ \text{m/s} \times 8.00\ \text{s}$

Answer:

$112\ \text{meters}$