Question

triangle abc with vertices a(2, 7), b(6, 5), and c(4, 1): 90° counterclockwise
a(__, __)
b(__, __)
c(__, __)
what are the new vertices for this triangle abc, when rotated at 90 degree counterclockwise using rule (-y, x).

Explanation:

Step1: Apply rule to point A

Given $A(2,7)$, using the rule $(-y,x)$, we get $A'(-7,2)$.

Step2: Apply rule to point B

Given $B(6,5)$, using the rule $(-y,x)$, we get $B'(-5,6)$.

Step3: Apply rule to point C

Given $C(4,1)$, using the rule $(-y,x)$, we get $C'(-1,4)$.

Answer:

$A'(-7,2)$
$B'(-5,6)$
$C'(-1,4)$