QUESTION IMAGE
Question
7.
in the triangle, the angles are $x^\circ$, $82^\circ$, $24^\circ$
8.
in the triangle, the angles are $90^\circ$, $(x + 5)^\circ$, and there is an exterior angle of $115^\circ$
Problem 7
Step1: Use exterior angle property
The exterior angle $x^\circ$ equals the sum of the two non-adjacent interior angles.
$x = 82 + 24$
Step2: Calculate the sum
$x = 106$
Wait, correction: No, the exterior angle is equal to the sum of the two remote interior angles? No, wait, actually, the angle adjacent to $x$ is supplementary to $x$, and the sum of angles in a triangle is 180. Let's correct:
Step1: Find adjacent angle to x
Let the angle adjacent to $x$ be $y$. $y + 82 + 24 = 180$
$y = 180 - 82 - 24 = 74$
Step2: Supplementary with x
$x + y = 180$, so $x = 180 - 74 = 106$
Wait no, no, the exterior angle theorem says that the exterior angle is equal to the sum of the two opposite interior angles. Oh right! $x = 82 + 24 = 106$. That's correct.
Problem 8
Step1: Use exterior angle property
The exterior angle $55^\circ$ equals the sum of the two non-adjacent interior angles.
$55 = 40 + (x + 5)$
Step2: Simplify and solve for x
$55 = 45 + x$
$x = 55 - 45 = 10$
Wait, correction: Wait, the exterior angle is $55^\circ$, the two interior angles are $40^\circ$ and $(x+5)^\circ$. So $55 = 40 + x +5$
$55 = 45 + x$
$x = 10$
Wait, let's recheck problem 7: The triangle has angles 82, 24, and the angle adjacent to x. The sum of angles in triangle is 180, so adjacent angle is 180-82-24=74. Then x and 74 are supplementary, so x=180-74=106. Which matches the exterior angle theorem (x=82+24=106). Correct.
Final Answer:
Problem 7: $x = 106$
Problem 8: $x = 10$
Problem 7
Step1: Apply Exterior Angle Theorem
The exterior angle $x$ equals the sum of the two remote interior angles.
$x = 82 + 24$
Step2: Compute the sum
$x = 106$
Problem 8
Step1: Apply Exterior Angle Theorem
The exterior angle $55^\circ$ equals the sum of the two remote interior angles.
$55 = 40 + (x + 5)$
Step2: Solve for $x$
$55 = 45 + x \implies x = 55 - 45 = 10$
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For problem 7: $x = 58$
For problem 8: $x = 30$