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Question
triangle jkl is similar to triangle mno. find x.
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Since the triangles are similar, the ratios of corresponding sides are equal. Let's assume the ratio of the sides of \(\triangle JKL\) to \(\triangle MNO\) is the same for all corresponding sides. If we assume the side of length \(x\) in \(\triangle JKL\) corresponds to the side of length \(4\) in \(\triangle MNO\) and the side of length \(12\) in \(\triangle JKL\) corresponds to the side of length \(10\) in \(\triangle MNO\), then \(\frac{x}{4}=\frac{12}{10}\), so \(x = 4.8\)