Question

1. triangle jkl with vertices j(-3, 4), k(5, 1), and l(1, -2); translated along the rule (x, y)→(x + 2, y - 4)

j(_, _)
k(_, _)
l(_, _)

Explanation:

Step1: Translate point J

For point $J(-3,4)$, apply the rule $(x,y)\to(x + 2,y - 4)$. So $x=-3$ and $y = 4$. Then $x+2=-3 + 2=-1$ and $y - 4=4-4 = 0$. So $J'(-1,0)$.

Step2: Translate point K

For point $K(5,1)$, with $x = 5$ and $y=1$. Then $x + 2=5+2=7$ and $y-4=1 - 4=-3$. So $K'(7,-3)$.

Step3: Translate point L

For point $L(1,-2)$, with $x = 1$ and $y=-2$. Then $x+2=1 + 2=3$ and $y-4=-2-4=-6$. So $L'(3,-6)$.

Answer:

$J'(-1,0)$
$K'(7,-3)$
$L'(3,-6)$