Question

triangle qrs has vertices q(8, -6), r(10, 5), and s(-3, 3). what are the coordinates of the vertices of the image of the triangle after a translation of t_{-7.6, 4.3}(x, y)? q = r = s =

Explanation:

Step1: Recall translation rule

For a translation $T_{a,b}(x,y)=(x + a,y + b)$, here $a=-7.6$ and $b = 4.3$.

Step2: Find coordinates of $Q'$

For $Q(8,-6)$, $x = 8$ and $y=-6$. Then $Q'=(8-7.6,-6 + 4.3)=(0.4,-1.7)$.

Step3: Find coordinates of $R'$

For $R(10,5)$, $x = 10$ and $y = 5$. Then $R'=(10-7.6,5 + 4.3)=(2.4,9.3)$.

Step4: Find coordinates of $S'$

For $S(-3,3)$, $x=-3$ and $y = 3$. Then $S'=(-3-7.6,3 + 4.3)=(-10.6,7.3)$.

Answer:

$Q'=(0.4,-1.7)$
$R'=(2.4,9.3)$
$S'=(-10.6,7.3)$