QUESTION IMAGE
Question
- trouver la qt de béton pour un mur de fondation de 1354\ de long par 8\ dépaisseur et une hauteur de 9-0\ (réponse en m³)
v = 135-4\ x 8\ x 9-0\
v = 135,333 x 0,667 x 9
v avec 5% de perte = 357,917 pi³ + 17,896 pi³ = 375,813 pi³
v avec 5% de perte = 375,813 pi³ / 35,32 = 10,64 m³
v en m³ = 375,813 pi³ / 35,32 = 10,64 m³
Step1: Convert units to feet
First, convert all measurements to decimal feet:
- Length: $135'-4'' = 135 + \frac{4}{12} = 135.333\ \text{ft}$
- Thickness: $8'' = \frac{8}{12} = 0.667\ \text{ft}$
- Height: $9'-0'' = 9\ \text{ft}$
Step2: Calculate volume in cubic feet
Multiply the three dimensions to get cubic feet:
$$V_{\text{ft}^3} = 135.333 \times 0.667 \times 9$$
$$V_{\text{ft}^3} = 812.001\ \text{ft}^3$$
Step3: Convert to cubic meters
Use the conversion factor $1\ \text{ft}^3 = 0.0283168\ \text{m}^3$:
$$V_{\text{m}^3} = 812.001 \times 0.0283168$$
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$22.99\ \text{m}^3$ (or approximately $23\ \text{m}^3$)