Question

try: solve the quadratic. \\( 3x^2 = 48 \\)

Explanation:

Step1: Divide both sides by 3

To isolate \(x^2\), we divide each side of the equation \(3x^2 = 48\) by 3.
\[
\frac{3x^2}{3}=\frac{48}{3}
\]
Simplifying both sides gives \(x^2 = 16\).

Step2: Take square root of both sides

Taking the square root of both sides of the equation \(x^2 = 16\), we get:
\[
x=\pm\sqrt{16}
\]
Since \(\sqrt{16} = 4\), we have \(x = \pm 4\).

Answer:

\(x = 4\) or \(x = - 4\)