Question

your turn
1 draw the image of each figure under the given transformation. record the coordinate of the image klm on the table.
$(x,y)\to(\frac{1}{2}x,y)$ hint: multiply x - values by 0.5 (same as 1/2) keep y - value the same
preimage image
$k(-2,1)\to k()$
$l(4, - 3)\to l()$
$m(-2,-4)\to m()$

Explanation:

Step1: Find coordinates of $K'$

For point $K(-2,1)$, apply the transformation $(x,y)\to(\frac{1}{2}x,y)$. Multiply the $x -$coordinate of $K$ by $\frac{1}{2}$ and keep the $y -$coordinate the same. So, $x_{K'}=\frac{1}{2}\times(-2)= - 1$ and $y_{K'}=1$. Thus, $K'(-1,1)$.

Step2: Find coordinates of $L'$

For point $L(4,-3)$, apply the transformation. Multiply the $x -$coordinate of $L$ by $\frac{1}{2}$ and keep the $y -$coordinate the same. So, $x_{L'}=\frac{1}{2}\times4 = 2$ and $y_{L'}=-3$. Thus, $L'(2,-3)$.

Step3: Find coordinates of $M'$

For point $M(-2,-4)$, apply the transformation. Multiply the $x -$coordinate of $M$ by $\frac{1}{2}$ and keep the $y -$coordinate the same. So, $x_{M'}=\frac{1}{2}\times(-2)=-1$ and $y_{M'}=-4$. Thus, $M'(-1,-4)$.

Answer:

$K'(-1,1)$
$L'(2,-3)$
$M'(-1,-4)$