QUESTION IMAGE
Question
two parallel lines are crossed by a transversal. what is the value of x? o x = 12 o x = 14 o x = 22 o x = 24 (5x + 5)° 115°
Step1: Use corresponding - angles property
Since the two parallel lines \(b\) and \(c\) are crossed by a transversal \(a\), the angle \((5x + 5)^{\circ}\) and the \(115^{\circ}\) angle are corresponding angles. Corresponding angles formed by two parallel lines and a transversal are equal. So, \(5x+5 = 115\).
Step2: Solve the equation for \(x\)
Subtract 5 from both sides of the equation \(5x+5 = 115\):
\[
$$\begin{align*}
5x+5 - 5&=115 - 5\\
5x&=110
\end{align*}$$
\]
Then divide both sides by 5: \(x=\frac{110}{5}=22\).
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\(x = 22\)