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two parallel lines are crossed by a transversal. what is the value of x…

Question

two parallel lines are crossed by a transversal. what is the value of x? o x = 12 o x = 14 o x = 22 o x = 24 (5x + 5)° 115°

Explanation:

Step1: Use corresponding - angles property

Since the two parallel lines \(b\) and \(c\) are crossed by a transversal \(a\), the angle \((5x + 5)^{\circ}\) and the \(115^{\circ}\) angle are corresponding angles. Corresponding angles formed by two parallel lines and a transversal are equal. So, \(5x+5 = 115\).

Step2: Solve the equation for \(x\)

Subtract 5 from both sides of the equation \(5x+5 = 115\):
\[

$$\begin{align*} 5x+5 - 5&=115 - 5\\ 5x&=110 \end{align*}$$

\]
Then divide both sides by 5: \(x=\frac{110}{5}=22\).

Answer:

\(x = 22\)