Question

two points located on $overleftrightarrow{jk}$ are $j(1,-4)$ and $k(-2,8)$. what is the slope of $overleftrightarrow{jk}$?
a. $-4$
b. $-2$
c. $-\frac{1}{4}$
d. $\frac{1}{4}$
e. $4$

Explanation:

Step1: Recall slope formula

The slope $m$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $m=\frac{y_2-y_1}{x_2-x_1}$

Step2: Assign values to variables

Let $(x_1,y_1)=(1,-4)$ and $(x_2,y_2)=(-2,8)$

Step3: Substitute into slope formula

$m=\frac{8-(-4)}{-2-1}=\frac{12}{-3}$

Step4: Calculate the final slope

$\frac{12}{-3}=-4$

Answer:

A. -4