Question

two teams are playing tug of war. team a pulls to the right with a force of 450 n. team b pulls to the left with a force of 415 n. what is the net force on the rope, and what is its direction? 35 n to the right 35 n to the left 865 n to the right 865 n to the left

Explanation:

Step1: Define positive - direction

Let the right - hand direction be positive. Team A's force $F_A = 450$ N and Team B's force $F_B=- 415$ N.

Step2: Calculate net force

The net force $F_{net}=F_A + F_B$. Substitute the values: $F_{net}=450+( - 415)$.
$F_{net}=450 - 415=35$ N.
Since the result is positive, the direction is to the right.

Answer:

35 N to the right