Question

two teams are pulling a heavy chest, located at point x. the teams are 4.6 meters away from each other. team a is 2.4 meters away from the chest, and team b is 3.2 meters away. their ropes are attached at an angle of 110°. which equation can be used to solve for angle a? law of sines: $\frac{sin(a)}{a}=\frac{sin(b)}{b}=\frac{sin(c)}{c}$

Explanation:

Step1: Identify Law of Sines components

In triangle AXB, angle A opposes side XB=3.2; angle X=110° opposes side AB=4.6.

Step2: Apply Law of Sines

Law of Sines: $\frac{\sin(A)}{\text{opposite side}} = \frac{\sin(X)}{\text{opposite side of } X}$. Thus, $\frac{\sin(A)}{3.2} = \frac{\sin(110^\circ)}{4.6}$.

Answer:

C. $\frac{\sin(A)}{3.2} = \frac{\sin(110^\circ)}{4.6}$