Question

two teams are pulling a heavy chest, located at point x. the teams are 4.6 meters away from each other. team a is 2.4 meters away from the chest, and team b is 3.2 meters away. their ropes are attached at an angle of 110°. which equation can be used to solve for angle a? law of sines: sin(a)/a = sin(b)/b = sin(c)/c

Explanation:

Step1: Identify sides and angles for law of sines

We have a triangle with side opposite angle A as 2.4, side opposite the 110° angle as 4.6.

Step2: Apply law of sines formula

The law of sines is $\frac{\sin(A)}{a}=\frac{\sin(B)}{b}=\frac{\sin(C)}{c}$. Here, $\frac{\sin(A)}{2.4}=\frac{\sin(110^{\circ})}{4.6}$.

Answer:

$\frac{\sin(A)}{2.4}=\frac{\sin(110^{\circ})}{4.6}$ (corresponding to the first option in the multiple - choice list)