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Question
u2 lesson 6/7: isosceles triangle and side - angle - side
- create a angle bisector of angle p, name the other end point j
isosceles triangle:
angle bisector:
reflexive property:
- prove △bpj≅△apj
| statement | reason |
|---|---|
| ∠____≅∠____ | |
| pj≅pj | reflexive property |
| side - angle - side congruence theorem (sas) |
isosceles triangle theorem: in an isosceles triangle, the base angles are congruent.
ap = pb so ∠a=∠b
Step1: Recall isosceles - triangle property
In an isosceles triangle $\triangle PAB$, the two equal - sides are $PA\cong PB$ by the definition of an isosceles triangle.
Step2: Recall angle - bisector property
Since $PJ$ is the angle - bisector of $\angle P$, then $\angle BPJ\cong\angle APJ$.
Step3: Apply SAS congruence
We have $PA\cong PB$, $\angle BPJ\cong\angle APJ$, and $PJ\cong PJ$ (reflexive property). By the Side - Angle - Side (SAS) congruence theorem, $\triangle BPJ\cong\triangle APJ$.
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| Statement | Reason |
|---|---|
| $\angle BPJ\cong\angle APJ$ | Definition of angle bisector |
| $PJ\cong PJ$ | Reflexive property |
| $\triangle BPJ\cong\triangle APJ$ | Side - Angle - Side congruence Theorem (SAS) |