Question

u3:04: unit 3 test
evaluate ( h(x) = 12 + x^2 ) for ( x = -5 )
( \bigcirc ) 2
( \bigcirc ) 37
( \bigcirc ) -13
( \bigcirc ) -2

Explanation:

Step1: Substitute \( x = -5 \) into the function

We have the function \( h(x) = 12 + x^2 \). Substitute \( x = -5 \) into it, so we get \( h(-5)=12+(-5)^2 \).

Step2: Calculate the square of -5

First, calculate \( (-5)^2 \). According to the rule of exponents, a negative number squared is positive, so \( (-5)^2 = 25 \).

Step3: Calculate the final result

Then, add 12 and 25. That is \( 12 + 25 = 37 \).

Answer:

37 (corresponding to the option "37")