QUESTION IMAGE
Question
use the diagram.
select two other names for $overleftrightarrow{st}$.
$overleftrightarrow{pt}$
$overleftrightarrow{st}$
$overleftrightarrow{qp}$
line m
line n
name a point that is not coplanar with points q, s, and t.
point is not coplanar with points q, s, and t.
Response
Part 1: Select two other names for $\overleftrightarrow{ST}$
Brief Explanations
- A line can be named using any two points on it or its given label. From the diagram, $\overleftrightarrow{ST}$ lies on line \( m \) and also passes through \( P \) (so $\overleftrightarrow{PT}$ is the same line as $\overleftrightarrow{ST}$ since \( S, P, T \) are colinear) and is labeled as line \( m \). $\overleftrightarrow{QP}$ is a different line (vertical), line \( n \) is also vertical, and the second $\overleftrightarrow{ST}$ is the same as the original. So the two other names are $\overleftrightarrow{PT}$ and line \( m \).
Brief Explanations
- Coplanar points lie on the same plane. Points \( Q \) is on line \( n \) (vertical), \( S, T \) are on line \( m \) (in the plane \( R \)). Point \( V \) is inside the plane \( R \)? Wait, no—wait, the plane \( R \) has line \( m \) and point \( V \)? Wait, no, looking at the diagram: \( Q \) is above the plane, \( S, T, P \) are on line \( m \) in plane \( R \), \( V \) is in plane \( R \)? Wait, no, maybe I misread. Wait, the plane \( R \) has the parallelogram, with \( V \) inside? No, wait, the problem says "not coplanar" with \( Q, S, T \). \( Q \) is on line \( n \) (perpendicular to plane \( R \)?), \( S, T \) are on line \( m \) (in plane \( R \)). So point \( V \): wait, no, maybe \( V \) is in plane \( R \), but \( Q \) is outside. Wait, no—wait, the points \( Q, S, T \): \( Q \) is on line \( n \), \( S, T \) on line \( m \). The plane containing \( Q, S, T \) would be the plane with line \( m \) and line \( n \) (since \( Q \) is on \( n \), \( S, T \) on \( m \), intersecting at \( P \)). Then point \( V \) is inside the parallelogram (plane \( R \))? Wait, no, maybe \( V \) is not on the same plane as \( Q, S, T \). Wait, the diagram: \( V \) is a point inside the parallelogram (plane \( R \)), \( Q \) is above, \( S, T \) on line \( m \) in plane \( R \). Wait, maybe I got it wrong. Wait, coplanar: three points determine a plane. \( Q, S, T \): \( S \) and \( T \) are on line \( m \), \( Q \) is on line \( n \) (intersecting \( m \) at \( P \)). So the plane is defined by lines \( m \) and \( n \). Point \( V \) is in the parallelogram (plane \( R \)), which is the same as the plane of \( m \) and \( n \)? Wait, no, the parallelogram is plane \( R \), and line \( n \) passes through \( P \) (in plane \( R \)) and \( Q \) (above). So \( Q, S, T \) are in the plane of \( m \) and \( n \) (which is plane \( R \)? Wait, maybe \( V \) is in plane \( R \), but maybe another point? Wait, the options—wait, the diagram has \( V \) as a point inside the parallelogram, \( Q \) above, \( S, T \) on line \( m \). So the point not coplanar with \( Q, S, T \) would be \( V \)? Wait, no, maybe I messed up. Wait, actually, \( Q \) is on line \( n \), \( S, T \) on line \( m \), so the plane containing \( Q, S, T \) is the plane with lines \( m \) and \( n \). Point \( V \) is in the parallelogram (plane \( R \)), which is the same as that plane? Wait, maybe the diagram shows \( V \) as a point inside the plane, but maybe the answer is \( V \)? Wait, no, let's think again. Coplanar points lie on the same plane. \( Q \) is above the plane (line \( n \) is perpendicular), \( S, T \) are on the plane (line \( m \) is on the plane). So the plane of \( S, T \) is the parallelogram plane \( R \). \( Q \) is not on plane \( R \), but \( S, T \) are. Wait, the question is "not coplanar with \( Q, S, T \)". So we need a point not on the plane that contains \( Q, S, T \). The plane containing \( Q, S, T \): \( S \) and \( T \) are on line \( m \) (in plane \( R \)), \( Q \) is on line \( n \) (intersecting \( m \) at \( P \), so line \( n \) passes through \( P \) (in plane \( R \)) and \( Q \) (outside). So the plane containing \( Q, S, T \) is the plane that includes line \( m \) and line \( n \) (since \( Q \) is on \( n \), \( S, T \) on \( m \), and \( n \) intersects \( m \) at \( P \)). So any point not on this plane. From the diagram, point \( V \) is inside the parallelogram (plane \( R \)), which is the same as the plane of \( m \) and \( n \)? Wait, maybe the diagram has \( V \) as a point in plane \( R \), so maybe I made a mistake.…
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$\boldsymbol{\overleftrightarrow{PT}}$, $\boldsymbol{\text{line } m}$