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use the distributive property to remove the parentheses. $-(-3y^2 - 1 +…

Question

use the distributive property to remove the parentheses.
$-(-3y^2 - 1 + 6u)$

Explanation:

Step1: Apply distributive property

The distributive property states that \(a(b + c + d)=ab+ac + ad\). Here, \(a=-7\), \(b = - 3y^{2}\), \(c=-1\), \(d = 6u\). So we have:
\(-7\times(-3y^{2})+(-7)\times(-1)+(-7)\times(6u)\)

Step2: Simplify each term

For the first term: \(-7\times(-3y^{2}) = 21y^{2}\)
For the second term: \(-7\times(-1)=7\)
For the third term: \(-7\times(6u)=-42u\)

Step3: Combine the terms

Combining the simplified terms, we get \(21y^{2}+7 - 42u\)

Answer:

\(21y^{2}+7 - 42u\)