Question

use the following emission scectra diagram to answer the folloing questions.
question 1 (1 point)
check the boxes for all of the elements present in unknown sample w.
a lithium (li)
b sodium (na)
c helium (he)
d potassium (k)
e cadmium (cd)
f hydrogen (h)

Explanation:

To determine the elements in Unknown W, we compare its emission spectrum (the black - lined bars) with the spectra of the known elements (the white - lined bars for each element):

Step 1: Analyze Lithium (Li)

The emission spectrum of Lithium (Li) has specific bar patterns at certain wavelengths. When we compare it with the spectrum of Unknown W, we can see that the bar patterns of Lithium do not match those of Unknown W. So, Lithium is not present.

Step 2: Analyze Sodium (Na)

Looking at the spectrum of Sodium (Na), we find that the bar patterns (the positions and widths of the emission lines) of Unknown W match those of Sodium. This means Sodium is present.

Step 3: Analyze Helium (He)

The emission spectrum of Helium (He) has a unique set of bar patterns. By comparing it with the spectrum of Unknown W, we observe that the patterns do not match. Thus, Helium is not present.

Step 4: Analyze Potassium (K)

The spectrum of Potassium (K) has its own distinct bar patterns. When we compare it with the spectrum of Unknown W, we can see that the patterns are different. So, Potassium is not present.

Step 5: Analyze Cadmium (Cd)

The emission spectrum of Cadmium (Cd) has specific bar patterns. Comparing it with the spectrum of Unknown W, we find that the patterns do not match. Hence, Cadmium is not present.

Step 6: Analyze Hydrogen (H)

The spectrum of Hydrogen (H) has a characteristic set of bar patterns. When we compare it with the spectrum of Unknown W, we see that the patterns do not match. So, Hydrogen is not present.

Answer:

b. Sodium (Na)