Question

use the graph to determine whether the function is even, odd, or neither

Explanation:

Step1: Recall even function symmetry rule

A function is even if its graph is symmetric about the $y$-axis (i.e., for every point $(x,y)$, $(-x,y)$ exists on the graph).

Step2: Recall odd function symmetry rule

A function is odd if its graph is symmetric about the origin (i.e., for every point $(x,y)$, $(-x,-y)$ exists on the graph).

Step3: Analyze the given graph

Observe the graph: for any point $(x,y)$ on the right side of the $y$-axis, the point $(-x,y)$ does not exist (so not symmetric about $y$-axis, not even). For any point $(x,y)$, the point $(-x,-y)$ does exist: e.g., $(2,0)$ and $(-2,0)$; $(1,1)$ and $(-1,-1)$ follow origin symmetry.

Answer:

Odd